The calculator compares the extraction of a solute between two immiscible solvents. It can model either a single extraction or several smaller extractions.
1. Check the definition of the partition coefficient
The calculator uses:
K = concentration in the organic layer ÷ concentration in the aqueous layer
Always check the order of the two concentrations. Reversing them gives a different value of K and an incorrect result.
A large value of K means that the solute has a greater preference for the organic solvent.
2. Enter the starting information
Supply the requested values:
- the initial mass or amount of solute;
- the volume of the aqueous solution;
- the volume of organic solvent;
- the partition coefficient, K;
- the number of extractions, if more than one is being performed.
The two solvent volumes may be entered in cm³, provided the same unit is used for both.
3. Select the extraction method
Choose between:
- one extraction using the complete volume of solvent;
- several extractions using smaller portions of solvent.
For repeated extractions, check whether the volume entered is the volume used for each extraction or the total volume being divided between the extractions.
4. Follow the single-extraction calculation
At equilibrium:
K = [solute]organic ÷ [solute]aqueous
Because concentration is amount divided by volume, the calculator uses both the partition coefficient and the solvent volumes to determine:
- the amount remaining in the aqueous layer;
- the amount transferred to the organic layer;
- the percentage of solute extracted.
For one extraction:
fraction remaining in the aqueous layer
= Vaqueous ÷ (Vaqueous + K × Vorganic)
The fraction extracted is:
1 − fraction remaining
5. Follow a multiple-extraction calculation
After each extraction, only a fraction of the solute remains in the aqueous layer.
If equal fresh portions of organic solvent are used:
fraction remaining after N extractions
= [Vaqueous ÷ (Vaqueous + K × Vorganic)]ᴺ
Here, (V_{\text{organic}}) is the volume used in each extraction.
The calculator applies the same equilibrium repeatedly and displays the amount remaining after each stage.
6. Compare the methods
Several smaller extractions are normally more effective than one extraction using the same total volume of solvent.
The advantage arises because each fresh portion of solvent establishes a new partition equilibrium and removes a fraction of the solute still remaining.
Check the reasoning
Before accepting the answer, check that:
- the two solvents are immiscible;
- the partition coefficient has been entered in the correct order;
- the same volume unit has been used for both solvents;
- the volume per extraction has not been confused with the total solvent volume;
- the correct number of extractions has been entered;
- the amounts in both layers add up to the original amount of solute.
The partition coefficient describes an equilibrium. The solute distributes between both layers—it is not normally transferred completely into one solvent.